S ort a given data in ascending order USING NESTED LOOP: a=eval(input("a:")) for i in range(len(a)): for j in range(len(a)-i-1): if a[j]>a[j+1]: a[j],a[j+1]=a[j+1],a[j] print(a) OUTPUT:
Posts
Python code to search a number in a sorted list
To search a number in a sorted list USING WHILE LOOP: a=eval(input("Insert a list: ")) val=int(input("value to find: ")) s=0 e=len(a)-1 while s<=e: m=(s+e)//2 if val==a[m]: print(val,"found at",m) break elif a[m]<val: s=m+1 else: e=m-1 else: print(val,"not found") OUTPUT:
Python program to check a number is prime or not
CHECK WHETHER A NUMBER IS PRIME OR NOT USING FOR LOOP: n=int(input("Enter a number:")) if n==1: print("neither a prime nor composite") elif n>1: for i in range(2,n): if n%i==0: print("It is not a prime") break else: print("It is a prime") OUTPUT:
Python program to find hcf of two numbers
TO FIND HCF OF TWO GIVEN NUMBERS USING WHILE LOOP: a=int(input("dividend")) b=int(input("divisor:")) rem=1 if a>b: while rem>0: if a%b==0: print("HCF is",b) break else: rem=a%b a=b b=rem else: print("dividend must be greater than divisor") OUTPUT:
PYTHON CODE TO REVERSE A GIVEN STRING
TO REVERSE A GIVEN STRING: METHOD -1 BY LOOPING AND JUST VIEWING THE REVERSE TEXT a=input("A:") j=len(a)-1 for i in range(len(a)-1,-1,-1): print(a[i] ,end="") OUTPUT- METHOD-2 BY CREATING A NEW STRING s=input("text:") c="" for i in range(len(s)-1,-1,-1): y=s[i] c=c+y print("The reverse of the given string is",c) OUTPUT-
Sum of the digits present in a list
PYTHON CODE FOR FINDING SUM OF DIGITS PRESENT IN A STRING METHOD-1 USING LOOP: a=input("Enter a string") s=0 for i in a: if i.isdigit(): s=s+int(i) print("Sum of the digit present in the string is:",s) OUTPUT: METHOD-2 my converting a string in list: a=input("Enter a string") m=list(a) s=0 for i in m: if i.isdigit(): s=s+int(i) print("Sum of the digit present in the string is:",s)